Tuesday, 24 April 2012

4 MAJU:CONTOH MIDYEAR EXAM PAPER

MID-YEAR EXAMINATION QUESTION                

PAPER1       ANSWER                                                                                                                                              1   Diagram 1 shows the relation between set M and set N
 set M              set N
      1------------>3
     2------------->4
     3------------>5
Diagram 1 
State  
(a)  the codomain of the relation.                 
        {3,4,5}
(b)  the type of the relation.                       [2 marks]
        one to one
2   Given f(x) = 2x – 5, find the value of q if f(q) = q.
          5                                                           [2 marks] 
3.   A function is defined by 
     f: x → 2x – 5.                                                                  
 Find                                                                                                  (a)  the object of image 7,                                    

(b)  the object which maps onto itself.              
                                                                    [3 marks]
      6,  5
4   Given the functions f : x → x – 1 and g : x →3/x , find            
(a)  the composite function gf,
        gf(x)= 3/(x-1)
(b)  the value of x if gf(x) = 9.                [3 marks]
        x = 4/3
5   Given the functions f : x → 2 – x and g : x → 4x2 + 1, 
      find the     value of x if gf = –fg.        [4 marks]
     x= 9/8
6   Given the function f : x → 5x + 3, find the value of x if   
       f (x)= -7
        x = -2                                                            [3 marks]
7   It is given that x = 1 is one of the roots of the quadratic        equation 2x2 – 3x + 1 = 0. Find the value of another root.                     x= 1/2                                                            [2 marks]
 8  Form a quadratic equation which has the roots of x = 3p and x = p in the form of ax2 + bx + c = 0, where a, b, and c are constants. Then, find the values of p if f(x) = ax2 + bx + c = 27 at the y-axis.                                                     [3 marks] 
      
9   It is given that the straight line y = c – 4x does not intersect the curve xy = 16. Find the range of c.       [3 marks]
       c <16
10  Calculate the value of k for which the line y = 5(x + 2) is a tangent to the curve y = x2 – 3x + k            [3 marks]
11  The curve y2 = p(x2 – 1) meets the straight line y = 3 only at one point. Find the negative value of p.        
            p = -36 
12  The quadratic equation 4x + c = 16 – (2 – x)2 has two equal roots. Find the value of c.   c = 13 

13  The curve y = 2x2 + 2tx + 3t – 4 touches the x-axis at the values of t = a and t = b, where a < b. Find the values of a and b.                                                                                                        [3 marks]
14  Find the range of values of k for which the line y = kx + 2 does not intersect the curve x2 + y2 = 2.                                [4 marks]
15  Find the range of values of k for which the line y + 4(kx + 1) = 0 meets the curve y = 2x2 + 7k.                                     [4 marks]
16  Solve the following simultaneous equations:
        x = y + 1
       (x – y) y = 1                                                 [2 marks]
        x= 2, y=1
17 Solve the simultaneous equations y = 4x – 1 and (x + 1)(y + 2) = 0.                                                                     [3 marks]
         x= -1, y= 5
          x= -1/4, y= -2
18  Solve the following simultaneous equations:
                  y    = 2x   and  y2  = 4x – 1
                                                                             [3 marks]
               x= 1/2, y= 1
19  Solve the simultaneous equations x – y = –1 and x2 + y2 = 25.
                                                                             [4 marks]
      x= -4, y= -3
       x= 3, y= 4
             
20  Solve the following simultaneous equations:
      x + 1    = 2y                    x2 + xy – 26  = 0
                                                                            [4 marks]
       x= -13/3, y= -5/3
        x= 4, y= 5/2
21  Solve the following simultaneous equations:
        2 log10 x  = log10 (x + y)
             x – y   = 0                                              [4 marks]
        x=0, y=0
        x=2, y=2
22Solve the equation 8x . 21 – x = 321 + 2x.                                                                                                                    [3 marks]
       x= - 1/2
23  Given that log3 x + 1 = 2 log9 (x + y), prove that 
       8x2 – 2xy – y2 = 0.                                      [4 marks]

24 Solve the equation log2 (5x + 2) + log2 (x – 1) = 2 + log2
(1 – 4x).                                                        

      x= 2/5     x= -1/3                                         [4 marks]
25  Given that y = kxm – 3 where k and m are constants. Find the values of k and m if y = 24 when x = 3 and y = 240 when  
 x = 9.            
                                                                        [4 marks]





MANUAL PENGGUNAAN KALKULATOR CASIO FX-570ES


MANUAL PENGGUNAAN KALKULATOR CASIO FX-570ES

1.Fraction
1        ½ x 2 1/3 = 5/6

2.Statistics
(a) Ungrouped data
Eg       Find min, standard deviation  of 
           1 2 3 4 5 6


Solution:
MODE
3   STAT
1 1-VAR
1 =2==3= 4= 5= 6 =
AC
SHIFT
1 STAT
5 Var      :  1 N =6
                       2 min= 3.5
                       3 stand dervtn= 1.7078
                      Varian?       =    stand dervtn2     


(b) Grouped data
Calculate mean and standard deviation
No of children
Frequency
0
8
1
10
2
7
3
5
4
1
      
Marks
Number of students
  1-10
5
11-20
8
21-30
20
31-40
10
 41-50
7

Find midpoint first, then follow the same steps.
Solution:
       MODE
3        STAT
SHIFT
MODE
â
4        STAT
Frequency    1: ON
        Key in data
        SHIFT 4
        Mean, stnd deviation......


  1. Matrix
MODE 6
AC
SHIFT 4
1: DIM
1:MatA.........5 :2X2....key in
SHIFT 4
1: DIM
1:MatB.........5 :2X2....key in
SHIFT 4
               (a) SHIFT 4   < 3 +  SHIFT 4 <4 = A+B



5     .Number Base-n
MODE 4
(a)     75 =
        SHIFT
        log    (BIN).....100101



(g) 
SHIFT
3 BASE
â
3   b1101
 +
SHIFT
3 BASE
4    o65
-
43
= 23

5 Graph Function
MODE 7
ALPHA     X
Key in   f(x)=x3-4x+9
Start....-3 =
End....4
Steps.....1 =
JADUAL JAWAPAN

6. Trigonometri
Ex7   :Polar

SHIFT
+   (Pol)
3,4  =
R=5, 0=53.1301

Ex 8   Rectangular
SHIFT
-           (Rec)
12,60  =
X=6,  Y=10.3923

7. QE...MODE 5(EQN) < 3
8. SE.. MODE 5(EQN) < 1


9.Prob. Distribution
MODE
3STAT
AC
SHIFT
1STAT
7Distr
1P(                  2Q(         3R(         4t
<                     <<           >>           >
















 

9999 99999

horror movie....contribute for student 5U...exc: Sakon Thai
http://www.youtube.com/watch?v=xqkACyCaBrc

enjoy the show!

STATISTICS


groupe presentation by form 4 A....
opps  salah class!

Monday, 23 April 2012